Simple molecules and covalent bonds
Atoms bond to achieve stability. Most atoms seek the stable electronic configuration of a noble gas (Group 0), which typically means having 8 electrons in their outer shell (the octet rule), or 2 electrons for Hydrogen and Helium (duet rule).
A covalent bond is formed when two atoms share a pair of electrons. This sharing allows both atoms to fill their outer shells without transferring electrons completely (which would form an ionic bond).
- Why does this happen? The positively charged nuclei of both atoms are attracted to the shared negative electron pair. This electrostatic attraction holds the atoms together.
- Core Requirement: You must be able to state that a covalent bond involves the sharing of a pair of electrons leading to noble gas configurations.
A covalent bond is the strong electrostatic attraction between a shared pair of electrons and the nuclei of two bonded atoms.
- Key phrase for exams: "Attraction between shared pair of electrons and nuclei."
- Note: Do not just say "sharing electrons." You must mention the attraction to the nuclei to get full marks.
Rules for Drawing:
- Use dots (•) for electrons from one atom and crosses (×) for electrons from the other.
- Only draw outer-shell electrons.
- Show the shared pair in the overlapping region of the two atoms.
- Ensure every atom achieves a full outer shell (8 or 2).
1. Hydrogen (H_2)
- Each H has 1 electron. They share 1 pair.
- Result: Each H sees 2 electrons (stable duet).
- Diagram: Two circles overlapping. One • and one × in the overlap. One • on the left H, one × on the right H.
2. Chlorine (Cl_2)
- Each Cl has 7 outer electrons. They share 1 pair.
- Result: Each Cl sees 8 electrons (stable octet).
- Diagram: Two circles overlapping. One • and one × in the overlap. Six other electrons around each Cl.
3. Water (H_2O)
- Oxygen (Group 6) has 6 outer electrons. Hydrogen has 1.
- O shares one pair with each of two H atoms.
- Result: O has 8 electrons (4 bonding pairs + 2 lone pairs). Each H has 2.
- Crucial Detail: Oxygen has two non-bonding pairs (lone pairs) remaining. Do not forget these!
4. Methane (CH_4)
- Carbon (Group 4) has 4 outer electrons. Hydrogen has 1.
- C shares one pair with each of four H atoms.
- Result: C has 8 electrons. Each H has 2.
- Crucial Detail: All 4 bonds are single covalent bonds.
| Lone Pairs on Central Atom |
|---|
| None |
| 3 pairs on each Cl |
| 2 pairs on O |
| None |
| 1 pair on N |
Mistake 1: Forgetting Lone Pairs
- Error: Drawing H_2O with only the bonding electrons.
- Correction: Oxygen has 6 valence electrons. 2 are shared. 4 remain as two lone pairs. You must draw these non-bonding electrons on the Oxygen atom.
Mistake 2: Wrong Number of Electrons
- Error: Drawing Carbon in CH_4 with only 6 outer electrons.
- Correction: Carbon starts with 4. It shares 4 pairs (8 total). Ensure the central atom has 8 electrons around it.
Mistake 3: Confusing Ionic and Covalent
- Error: Drawing arrows showing electron transfer in covalent molecules.
- Correction: Covalent bonds involve sharing, not transfer. Use overlapping circles or lines to show sharing.
When to use: Whenever asked to 'describe' or 'draw' the bonding in a molecule.
Why examiners accept this: Examiners look for specific visual evidence of understanding:
- Correct count: The total number of dots/crosses must match the valence electrons of the atoms.
- Full shells: Every atom (except H) must have 8 electrons around it; H must have 2.
- Lone pairs: Non-bonding electrons must be shown on the correct atoms.
Example of correct phrasing/drawing:
For Ammonia (NH_3):
- Draw N in the center with 5 valence electrons (e.g., 5 crosses).
- Draw three H atoms around it, each with 1 electron (e.g., 1 dot).
- Show three overlapping regions where one cross and one dot meet (3 bonding pairs).
- Show one lone pair (2 crosses) remaining on the Nitrogen atom.
- Tip: Clearly label 'lone pair' or ensure it is visually distinct from bonding pairs.
1. Low Melting and Boiling Points
- Structure: Simple molecular substances consist of distinct, small molecules held together by covalent bonds.
- Explanation: The covalent bonds within the molecule are strong, but the forces between the molecules (intermolecular forces) are weak.
- Result: Little energy is needed to overcome these weak intermolecular forces to melt or boil the substance. The covalent bonds themselves do not break during melting/boiling.
2. Poor Electrical Conductivity
- Structure: Electrons in covalent bonds are localized (fixed) between specific atoms.
- Explanation: There are no free-moving charged particles (no delocalized electrons and no ions).
- Result: Electricity cannot flow. This applies to both solid and liquid states (unlike ionic compounds, which conduct when molten).
For Low Melting/Boiling Points:
- Context: When asked to explain physical properties.
- Key Phrase: "Weak intermolecular forces between molecules require little energy to overcome."
- Why this works: It distinguishes between the strong intramolecular bonds (which don't break) and the weak intermolecular forces (which do). Examiners reject answers that say "bonds are broken" during melting.
For Poor Conductivity:
- Context: When asked why a covalent substance does not conduct electricity.
- Key Phrase: "There are no free-moving charged particles / ions / delocalized electrons."
- Why this works: It directly addresses the requirement for charge carriers in conduction. Be specific: do not just say "no electrons." Say "no free or delocalized electrons" and "no ions."
For supplement molecules, you must handle multiple bonds (sharing more than one pair).
1. Oxygen (O_2) - Double Bond
- Each O has 6 outer electrons.
- To get 8, each needs to share 2 pairs.
- Diagram: Two overlapping circles. In the overlap: two dots and two crosses (4 electrons total). Each O also has two lone pairs (4 non-bonding electrons).
2. Carbon Dioxide (CO_2) - Double Bonds
- C has 4 outer electrons. Each O has 6.
- C shares 2 pairs with the left O and 2 pairs with the right O.
- Diagram: O=C=O structure. Two double bonds (two shared pairs each). Each O has two lone pairs. C has no lone pairs.
3. Nitrogen (N_2) - Triple Bond
- Each N has 5 outer electrons.
- To get 8, each needs to share 3 pairs.
- Diagram: Two overlapping circles. In the overlap: three dots and three crosses (6 electrons total). Each N also has one lone pair (2 non-bonding electrons).
4. Ethene (C_2H_4) - Double Bond between Carbons
- Each C shares 2 pairs with the other C.
- Each C also shares 1 pair with two H atoms.
- Diagram: H₂C=CH₂. The central C-C bond is a double bond (two shared pairs). Each C has no lone pairs.
Mistake 1: Incorrect Electron Count in CO_2
- Error: Drawing single bonds between C and O.
- Correction: Carbon needs 4 bonds to be stable. Oxygen needs 2. You must draw double bonds (two shared pairs) for both C-O connections.
Mistake 2: Forgetting Lone Pairs in N_2 or O_2
- Error: Drawing only the bonding electrons.
- Correction: In N_2, each N has 1 lone pair. In O_2, each O has 2 lone pairs. These are essential for the octet rule.
Mistake 3: Confusing Intermolecular Forces with Bonds
- Error: Saying "weak bonds between molecules."
- Correction: Use the term intermolecular forces. They are not bonds.
When to use: When drawing O_2, N_2, CO_2, or C_2H_4.
Why examiners accept this: They verify that you understand valency requirements:
- Carbon forms 4 bonds.
- Nitrogen forms 3 bonds (plus 1 lone pair).
- Oxygen forms 2 bonds (plus 2 lone pairs).
Example for N_2:
- Draw two N atoms.
- Show three shared pairs (6 electrons) between them.
- Show one lone pair on each N atom.
- Check: Does each N have 8 electrons? Yes (6 bonding + 2 lone).
Example for CO_2:
- Draw C in the middle, O on sides.
- Show two shared pairs between C and left O.
- Show two shared pairs between C and right O.
- Show two lone pairs on each O.
- Check: Does C have 8 electrons? Yes (4 bonding pairs). Do Os have 8? Yes (2 bonding pairs + 2 lone pairs).