Home Notes Papers

Energy, work and power

Paper 1Paper 2Paper 3Paper 4

This topic is examined in Paper 1, Paper 2, Paper 3 and Paper 4.

Energy Stores and Transfers (LO1, LO2)
What is an energy store?
Modern Cambridge physics describes energy as being 'stored' in different ways. When you see a question about where energy comes from or goes to, identify the store.

Energy Store Description
Kinetic Stored by an object due to its motion.
Gravitational Potential (gPE) Stored by an object due to its position in a gravitational field (height).
Chemical Stored in the bonds between atoms and molecules (e.g., food, batteries, fuels).
Elastic (Strain) Stored when an object is stretched or compressed.
Nuclear Stored in the nucleus of an atom.
Electrostatic Stored by charged particles due to their position relative to other charges.
Internal (Thermal) Stored by the random motion of particles within a substance (related to temperature).

How is energy transferred?
Energy moves from one store to another via four main pathways:

  1. Mechanically: By the action of forces (e.g., pushing a box).
  2. Electrically: By the movement of electric charges (currents).
  3. By Heating: Due to a temperature difference (conduction, convection, radiation).
  4. By Waves: Electromagnetic waves (light), sound waves, or other wave types.

Note: Energy is never 'created' or 'destroyed', only transferred.

Complex Energy Transfers and Sankey Diagrams (LO6)
In complex processes, energy passes through intermediate stores.

Example: A hydroelectric power station

  1. Water behind a dam has high Gravitational Potential Energy store.
  2. As water falls, gPE transfers mechanically to the Kinetic Energy store of the moving water.
  3. The moving water hits turbine blades, transferring energy mechanically to the Kinetic Energy store of the turbine.
  4. The generator converts this to Electrical Energy (work done electrically).

Interpreting Sankey Diagrams:
Sankey diagrams visualize these transfers. The width of the arrow is proportional to the amount of energy.

  • Thick arrows: Large energy transfer (useful or wasted).
  • Thin arrows: Small energy transfer.
  • Downward branches: Usually represent wasted energy (often thermal) dissipated to the surroundings.

To analyze a complex Sankey diagram:

  1. Identify the total input width.
  2. Trace the main path to the useful output.
  3. Identify any intermediate stores if shown (e.g., kinetic energy of a moving car before braking).
  4. Sum of all output widths must equal the input width (Conservation of Energy).
Work Done (W)
Definition: Work done is the energy transferred when a force moves an object.

Equation:
W = F \times d

Where:

  • W is work done (or energy transferred) in joules, J.
  • F is the force applied in newtons, N.
  • d is the distance moved by the point of application of the force in the direction of the force, in metres, m.

Key Principle:
The work done on an object is equal to the energy transferred to its store. For example, if you lift a box, the work done by your muscles equals the gain in the box's gravitational potential energy store.

Kinetic Energy (E_k)
Definition: The energy stored in an object due to its motion.

Equation:
E_k = \frac{1}{2}mv^2

Where:

  • E_k is kinetic energy in joules, J.
  • m is the mass of the object in kilograms, kg.
  • v is the speed (velocity magnitude) of the object in metres per second, m/s.

Note: Speed is squared, so doubling the speed quadruples the kinetic energy.

Gravitational Potential Energy Change (\Delta E_p)
Definition: The change in energy stored due to a change in vertical height.

Equation:
\Delta E_p = mg\Delta h

Where:

  • \Delta E_p is the change in gravitational potential energy in joules, J.
  • m is the mass of the object in kilograms, kg.
  • g is the gravitational field strength (approx. 9.8 \text{ N/kg} or 10 \text{ N/kg} depending on the paper) in newtons per kilogram, N/kg.
  • \Delta h is the change in vertical height in metres, m.

Note: Use \Delta h for any change in height. If lifting up, energy increases. If falling down, energy decreases.

Power (P)
Definition: Power is the rate of energy transfer or the rate of work done.

Equations:
P = \frac{W}{t} \quad \text{or} \quad P = \frac{\Delta E}{t}

Where:

  • P is power in watts, W (where 1 \text{ W} = 1 \text{ J/s}).
  • W is work done in joules, J.
  • \Delta E is energy transferred in joules, J.
  • t is the time taken in seconds, s.

Note: Always ensure time is in seconds. If given in minutes, multiply by 60.

Efficiency (\eta)
Definition: Efficiency is a measure of how much of the input energy is converted into useful output.

Equations:
\text{Efficiency} = \frac{\text{Useful Energy Output}}{\text{Total Energy Input}} \times 100%

or

\text{Efficiency} = \frac{\text{Useful Power Output}}{\text{Total Power Input}} \times 100%

Where:

  • Efficiency is expressed as a percentage, %.
  • Useful output and total input must be in the same units (both energy in J or both power in W).

Note: Efficiency is always less than 100% because some energy is always wasted (usually as thermal energy to the surroundings).

Calculating Work Done and Power
Scenario: A student lifts a 2.0 \text{ kg} textbook vertically by 1.5 \text{ m} in 3.0 \text{ s}. Calculate the work done and the power output.

Step 1: Identify forces.
To lift the book at constant speed, the upward force F must equal the weight of the book.
F = mg = 2.0 \times 9.8 = 19.6 \text{ N}

Step 2: Calculate Work Done (W).
The force acts in the direction of motion (vertical).
W = F \times d = 19.6 \times 1.5 = 29.4 \text{ J}
(This equals the gain in gravitational potential energy store).

Step 3: Calculate Power (P).
P = \frac{W}{t} = \frac{29.4}{3.0} = 9.8 \text{ W}

Energy Resources and the Sun (LO9, LO12)
The Main Source:
Radiation from the Sun is the main source of energy for almost all resources on Earth.

Resource Connection to Sun / Other Sources
Fossil Fuels Stored chemical energy from ancient plants/animals that captured solar energy via photosynthesis.
Biofuels Chemical energy from recent plants (solar origin).
Wind Caused by uneven heating of the Earth's surface by infrared and other electromagnetic waves from the Sun.
Hydroelectric Solar energy evaporates water, which falls as rain in high places (gPE).
Wave/Tidal Waves are driven by wind (solar). Tides are primarily due to gravitational attraction of the Moon/Sun.
Solar Cells Direct conversion of light/electromagnetic radiation to electrical energy.
Geothermal Heat from Earth's interior (radioactive decay and residual formation heat). NOT solar.
Nuclear Energy from nuclear fusion in the Sun (LO13) or fission on Earth. NOT solar.

Note: Geothermal, Nuclear, and Tidal are the main exceptions to the 'Sun is the source' rule.

⚠︎ Notation Confusion: Work vs. Weight
The Error:
Students often confuse the symbol for Work Done (W) with Weight (W or F_g). In the formula W = Fd, if lifting an object, F is the weight. Writing W = W_{eight} \times d is confusing and prone to error.

The Correction:

  1. Use clear symbols. Let W denote Work Done.
  2. Let F_g or mg denote Weight/Force due to gravity.
  3. When lifting vertically: W = mg \times h. Here, mg is the force, and h is the distance.

Why this matters:
If you write W = W \times d, it looks like W(1-d)=0, which is mathematically ambiguous. Always distinguish between the energy transferred (W) and the force causing it (F_g).

The Error: Horizontal Distance in Vertical Work
Students often include horizontal width or distance when calculating work done against gravity.

The Correction:
Work done against gravity depends only on the vertical height change (\Delta h). The path taken (straight up, zig-zag, stairs) does not matter for the gain in gPE. However, for work done by a person, if they walk horizontally while holding the weight, no work is done against gravity during the horizontal part because the force (up) is perpendicular to motion (horizontal).

Rule: Only include distance moved in the direction of the force.

Describing Energy Transfers Correctly
Context: When asked to 'describe the energy transfers' in a process.

Examiner Acceptance:
Use the phrase: 'Energy is transferred mechanically from the gravitational potential store to the kinetic store.'

Why this works:

  1. It identifies the source store (gravitational potential).
  2. It identifies the destination store (kinetic).
  3. It specifies the pathway (mechanically/by forces).

Avoid: Saying 'Potential energy turns into kinetic energy.' This is vague. Cambridge requires specific store names and transfer pathways.

Example: For a falling ball:
Correct: 'Energy transfers mechanically from the gravitational potential store to the kinetic store.'
Incorrect: 'The ball loses potential energy and gains speed.'

Context: When asked to explain why efficiency is less than 100%.

Examiner Acceptance:
Use the phrase: 'Some energy is dissipated to the surroundings as thermal energy (or sound).

Why this works:
It acknowledges that energy is conserved but 'wasted' into stores not useful for the intended purpose. The keyword dissipated is highly valued.

Example: For a light bulb:
Correct: 'Electrical work done transfers energy to the thermal store of the filament and then radiates as light. However, significant energy is dissipated to the surroundings as thermal energy.'
Incorrect: 'Energy is lost.'

Past Paper Style Questions
Q:
A car of mass 1200 kg accelerates from rest to a speed of 20 m/s. Calculate the gain in kinetic energy.
A:
E_k = \frac{1}{2}mv^2 = 0.5 \times 1200 \times 20^2 = 240,000 \text{ J} (or 240 kJ).
Q:
State the principle of conservation of energy.
A:
Energy cannot be created or destroyed; it can only be transferred from one store to another or transformed from one form to another.
Q:
Explain why wind energy is considered an indirect form of solar energy.
A:
Wind is caused by uneven heating of the Earth's surface by infrared and other electromagnetic waves from the Sun. This creates pressure differences that move air masses.
Q:
A pump lifts 50 kg of water vertically through a height of 10 m in 20 s. Calculate the power output of the pump.
A:
Force (weight) F = mg = 50 \times 9.8 = 490 \text{ N}. Work done W = Fd = 490 \times 10 = 4900 \text{ J}. Power P = W/t = 4900 / 20 = 245 \text{ W}.
Q:
A device has a total energy input of 1000 J. If it is 80% efficient, calculate the useful energy output.
A:
Useful Output = 0.80 \times 1000 = 800 \text{ J}.
Q:
Identify the main energy store in a battery and the type of transfer when it powers a lamp.
A:
Store: Chemical. Transfer: Electrically (from chemical store to electrical work done, then to thermal/light stores).
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